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Answer: XF points toward the center of the circle
This situation is characteristic of the uniform circular motion (figure attached), where [tex]\vec{V}[/tex] is the velocity vector, whose direction is perpendicular to the radius [tex]r[/tex] of the trajectory.
The other thing that can be observed is that its acceleration [tex]\vec{a}[/tex] is directed toward the center of the circumference (that's why it's called centripetal acceleration).
Now, according to Newton's 2nd law, the force [tex]\vec{F}[/tex] is directly proportional and in the same direction as the acceleration:
[tex]\vec{F}=m.\vec{a}[/tex]
Therefore the net force XF resulting from the movement points towards the center of the circle and is called Centripetal Force.
Therefore the correct option is 5.

From Newton's second law of motion, the motion points toward the center of the circle.
Newton's second law of motion
Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
where;
- m is mass of the object
- a is the acceleration of the object
For a circular motion, the force acts inward to keep the object moving in the circular path.
Thus, from Newton's second law of motion, the motion points toward the center of the circle.
Learn more about Newton's second law of motion here: https://brainly.com/question/3999427