(a) [tex]1.25\cdot 10^{-14} J[/tex]
The change in potential energy of the electron is given by:
[tex]\Delta U=q E d[/tex]
where
[tex]q=1.6\cdot 10^{-19}C[/tex] is the magnitude of the electron's charge
[tex]E=150 N/C[/tex] is the magnitude of the electric field
d = 520 m is the distance through which the electron has moved
Substituting into the equation, we find
[tex]\Delta U=(1.6\cdot 10^{-19}C)(150 N/C)(520 m)=1.25\cdot 10^{-14} J[/tex]
(b) 78 kV
The potential difference the electron has moved through is given by
[tex]\Delta V=Ed[/tex]
where
[tex]E=150 N/C[/tex] is the magnitude of the electric field
d = 520 m is the distance through which the electron has moved
Substituting into the equation, we find
[tex]\Delta V=Ed=(150 N/C)(520 m)=78,000 V=78 kV[/tex]
