Answer:
x=-2 is the removable discontinuity of the function.
Step-by-step explanation:
Given that
[tex]f(x) = \frac{x^2-4x-12}{x+2}[/tex]
We have to find the discontinuity of the function.
We find the numerator has got a factor as denominator because
[tex]x^2-4x-12 =(x-6)(x+2)[/tex]
x+2 can be cancelled and the function would be
x-6 if x not equals -2
Thus the function is discontinuous at x=-2
The discontinuity is removable if f(-2) is defined as =-8
Thus x=-2 is a removable discontinuity of the function.
