Answer:
1.89 is the standard deviation of households who own a riding mower
Step-by-step explanation:
Let the random variable X denote the number of households owning a riding lawn mower. From the given information, X will be a Binomial random variable with parameters; n = 17 and p = 30% = 0.3
The standard deviation of X;
[tex]\sqrt{n*p*(1-p)}[/tex]
[tex]\sqrt{17*0.3*(1-0.3)} =1.89[/tex]