Answer:
(B)
Step-by-step explanation:
It is given that KLM and NPQ are the two triangles in which ∠L=∠P, ∠K=∠N and ∠M=∠Q. Also, KL=16, LM=22, KM=12, NP=8, PQ=11 and NQ=6.
Now, From ΔKLM and ΔNPQ, applying the basic proportionality theorem, we have
[tex]\frac{LK}{NP}=\frac{LM}{PQ}=\frac{KM}{NQ}[/tex]
[tex]\frac{16}{8}=\frac{22}{11}=\frac{12}{6}=\frac{2}{1}[/tex]
which holds, and thus the two triangles are similar as their corresponding sides are in the ratio 2:1 from KLM to NPQ.
Also, it is given that ∠L=∠P, ∠K=∠N and ∠M=∠Q that is the corresponding angles are congruent.
therefore, the two triangles similar because their corresponding angles are congruent and their corresponding side lengths are in the ratio 2:1 from KLM to NPQ.
Hence, option B is correct.