use the pythagorean theorem to find the missing part of A
[tex]{8}a^{2} + {b}^{2} = {10}^{2} [/tex]
[tex]64 + {b}^{2} = 100[/tex]
remove 64 on both sides
64-64+b^2=100-64
b^2=36
find the square root for 36
[tex] \sqrt{{b}^{2} } = \sqrt{36} [/tex]
b=6
remember that for later
use Pythagorean theorem again to find the missing side for B
[tex] {a}^{2} + {8}^{2} = {17}^{2} [/tex]
[tex] {a}^{2} + 64 = 289[/tex]
remove 64 both sides
a^2+64-64=289-64
a^2=225
find square root for 225
[tex] \sqrt {a}^{2} = \sqrt{225} [/tex]
a=15
add the sides together
6 (b) + 15 (a) = 21
