Answer:
First table
Step-by-step explanation:
We have to find the set of value which could be from a direct proportion.
We know that
Direct proportion :
When x is directly proportional to y
[tex]x\propto y[/tex]
[tex]x=ky[/tex]
Where k=Proportionality constant
[tex]k=\frac{x}{y}[/tex]
K remain constant when x and y are in direct proportion
From first table
[tex]k=\frac{\frac{1}{2}}{6}=\frac{1}{12}[/tex]
[tex]k=\frac{1}{12}[/tex]
[tex]k=\frac{2}{24}=\frac{1}{12}[/tex]
[tex]K=\frac{3}{36}=\frac{1}{12}[/tex]
When x and y are both varies then ratio of x and y remain constant.Hence, it is in direct proportion.
From second table
[tex]k=\frac{0}{0}=[/tex] not ]define
[tex]k=\frac{1}{1}=1[/tex]
It is not direct proportion because k does not remain constant.
From third table
[tex]k=\frac{0}{2}=0[/tex]
[tex]k=\frac{2}{4}=\frac{1}{2}[/tex]
It is not direct proportion because k does not remain constant.
