Answer:
It's is A and D.
Step-by-step explanation:
Tan^2 theta cos 2theta
= (sin^2 theta / cos^2 theta )( 2 cos^2 theta - 1)
= 2 sin^2 theta - sin^2 theta / cos^2 theta
= 2 sin^2 theta - tan^2 theta.
Tan^2 theta cos 2theta
= ( 1 / cot^2 theta) * cos 2theta
= cos 2theta / cot^2 theta.
The simplified forms of the expression [tex]tan^2(\theta)cos(2\theta)[/tex] would be[tex]2 sin^2 \theta- tan^2 \theta.[/tex] and [tex]\frac{ cos 2\theta}{ cot^2 \theta}[/tex]. So It's is A and D.
Trigonometric functions are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.
The expression is given as
[tex]tan^2(\theta)cos(2\theta)[/tex]
The simplified form
[tex]= (sin^2 \theta / cos^2 \theta)( 2 cos^2 \theta- 1)\\= 2 sin^2 \theta- sin^2 \theta/ cos^2 \theta\\= 2 sin^2 \theta- tan^2 \theta.[/tex]
similarly the simplified form
[tex]tan^2(\theta)cos(2\theta)[/tex]
[tex]= ( 1 / cot^2 \theta) \times cos 2 \theta\\\\=\frac{ cos 2\theta}{ cot^2 \theta}[/tex]
Learn more about trigonometric;
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