Respuesta :

wegnerkolmp2741o

Answer:

(p^2−6) (1-q(p^2-6))

Step-by-step explanation:

p^2−6−q·(p^2−6)^2

Put parentheses around the P^2-6 at the beginning of the expression

(p^2-6) -q (p^2−6)^2

Factor out (p^2−6)

(p^2−6) (1-q(p^2-6))

Assignment: [tex]\bold{Factor \ Equation: \ p^2-6-q\left(p^2-6\right)^2}[/tex]

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Answer: [tex]\boxed{\bold{\left(p^2-6\right)\left(-p^2q+6q+1\right)}}[/tex]

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Explanation: [tex]\downarrow\downarrow\downarrow[/tex]

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[ Step One ] Factor Out Common Term [tex]\bold{\left(p^2-6\right)}[/tex]

[tex]\bold{\left(p^2-6\right)\left(-q\left(p^2-6\right)+1\right)}[/tex]

[ Step Two ] Expand [tex]\bold{-q\left(p^2-6\right)+1}[/tex]

[tex]\bold{-p^2q+6q+1}[/tex]

[ Step Three ] Rewrite Equation

[tex]\bold{\left(p^2-6\right)\left(-p^2q+6q+1\right)}[/tex]

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[tex]\bold{\rightarrow Mordancy \leftarrow}[/tex]

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