A motorbike uses petrol and oil mixed in the ratio 13:2
a)how much of each is there in 30 litres of mixture ?
b) how much petrol would be mixed with 500 ml of oil?

Respuesta :

Answer:

Part A) [tex]26\ liters[/tex] of petrol and [tex]4\ liters[/tex] of oil

part B) [tex]3.25\ liters[/tex] or [tex]3,250\ ml[/tex] of petrol

Step-by-step explanation:

Part A) How much of each is there in 30 liters of mixture ?

Let

x-----> the amount of liters of petrol

y----> the amount of liters of oil

we know that

[tex]\frac{x}{y}=\frac{13}{2}[/tex]

[tex]x=\frac{13}{2}y[/tex] -----> equation A

[tex]x+y=30[/tex] ---> equation B

substitute equation A in equation B

[tex]\frac{13}{2}y+y=30[/tex]

[tex]\frac{15}{2}y=30[/tex]

[tex]y=30*2/15=4\ liters[/tex]

Find the value of x

[tex]x=\frac{13}{2}(4)=26\ liters[/tex]

Part B) How much petrol would be mixed with 500 ml of oil?

Convert ml to l

[tex]500\ ml=0.50\ l[/tex]

we know that

using proportion

[tex]\frac{13}{2}=\frac{x}{0.5}\\ \\x=13*0.5/2\\ \\x=3.25\ l[/tex]