Answer:
Part A) [tex]26\ liters[/tex] of petrol and [tex]4\ liters[/tex] of oil
part B) [tex]3.25\ liters[/tex] or [tex]3,250\ ml[/tex] of petrol
Step-by-step explanation:
Part A) How much of each is there in 30 liters of mixture ?
Let
x-----> the amount of liters of petrol
y----> the amount of liters of oil
we know that
[tex]\frac{x}{y}=\frac{13}{2}[/tex]
[tex]x=\frac{13}{2}y[/tex] -----> equation A
[tex]x+y=30[/tex] ---> equation B
substitute equation A in equation B
[tex]\frac{13}{2}y+y=30[/tex]
[tex]\frac{15}{2}y=30[/tex]
[tex]y=30*2/15=4\ liters[/tex]
Find the value of x
[tex]x=\frac{13}{2}(4)=26\ liters[/tex]
Part B) How much petrol would be mixed with 500 ml of oil?
Convert ml to l
[tex]500\ ml=0.50\ l[/tex]
we know that
using proportion
[tex]\frac{13}{2}=\frac{x}{0.5}\\ \\x=13*0.5/2\\ \\x=3.25\ l[/tex]