Respuesta :

superman1987

Answer:

As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.

Explanation:

  • Firstly, we must mention that:

The solubility of KNO₃ per 100.0 g of water at 40.0 °C = 63.0 g.

The solubility of KNO₃ per 100.0 g of water at 0.0 °C = 14.0 g.

  • So, at 40.0 °C, 51.0 g of KNO₃ will be completely dissolved in water.
  • As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.
pstnonsonjoku

When the solution is cooled from  40 ∘c to 0 ∘c, 37 g of KNO3 will precipitate.

The solubility of a substance refers to the amount of substance that is soluble in water at a given temperature. It is very necessary to note that solubility is highly temperature dependent.

The solubility of KNO3 at 40 ∘c = 63.0 g per 100.0 g of water

The solubility of KNO3 at  0 ∘c = 14.0 g per 100.0 g of water

When the solution is cooled from  40 ∘c to 0 ∘c, 51 g - 14.0 g = 37 g of KNO3 will precipitate.

Learn more about solubility: https://brainly.com/question/13620168

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