297.18 grams of iron are produced when 425 g of iron (III) oxide ( Fe₂O₃) are reacted.
What is Stoichiometry ?
Stoichiometry helps us use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.
What is Balanced Chemical equation ?
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given balanced equation is
Fe₂O₃ + 3H₂ → 2Fe + 3H₂O
Here 1 mol of Fe₂O₃ react with 3 mol of H₂ to produce 2 mol of Fe.
According to stoichiometry
Mass of Fe = 425 g Fe₂O₃ × [tex]\frac{2\ \text{mol Fe}}{1\ \text{mol}\ Fe_2O_3}[/tex]
= 425 g Fe₂O₃ × [tex]\frac{2 \times 55.8\ g\ Fe}{159.6\ g\ Fe_2O_3}[/tex]
= 425 g Fe₂O₃ × [tex]\frac{111.6\ g\ Fe}{159.6\ g\ Fe_2O_3}[/tex]
= 297.18 g Fe
Thus, from above conclusion we can say that 297.18 grams of iron are produced when 425 g of iron (III) oxide ( Fe₂O₃) are reacted.
Learn more about the Stoichiometry here: https://brainly.com/question/14935523
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