Answer:
The given function is , g(x)= - x + 2
[tex]x_{1}=4, g(4)=-4+2=-2,g(-2)=-(-2)+2=4, g(4)=-4+2=-2,g(-2)=-(-2)+2=4[/tex]
For values of [tex](x_{1})[/tex], [tex]g(x_{1})[/tex] is the sequence, -2,4,-2,4,-2,4........
[tex]x_{2}=2, g(x_{2})=-2+2=0, g(0)=-0+2=2,g(2)=-2+2=0,g(0)-0+2=2\\\\ x_{3}=1,g(x_{3})=-1+2=1, g(1)=-1+2=1,[/tex]
For values of [tex](x_{2})[/tex], [tex]g(x_{2})[/tex] is the sequence, 0,2,0,2........
For values of [tex](x_{3})[/tex], [tex]g(x_{3})[/tex] is the sequence, 1,1,1,1,........
For initial value, of 4,the sequence converges to two values that is -2, 4.
For initial value of 2, the sequence again converges to two values which are 0,2.
For initial value of 1, the sequence converges to one value which is 1.
→→First Iterative value that is (-2)=Second iterative value (0) + 2 ×Third iterative value(1)
→→ First Iterative value that is (4)=Second iterative value (2) + 2 ×Third iterative value(1)
