Respuesta :

sherry318
The third graph because when r is at 0, s is greater than 0 so it cannot start at the origin. If you look at the values of s, it is increasing at a constant rate of 1, so slope is positive.
thaovtp1407

Answer:

Picture 3

Step-by-step explanation:

Given the table of r and s already

Now we need to find the slope (m) of the equation that models this situation.

m = [tex]\frac{s2-s1}{r2-r1}[/tex] = [tex]\frac{11-10}{1-0}[/tex] = 1

Because the value of the slope is greater than 1, so the line is going up, then we have picture 2 and 3 left

We have the standard form of a linear line is: s = mr+ b

<=> s = m + b (1)

Then we substitute the the value of s=11 and r= 0 into the equation (1) , we have:

11 = 0 + b

<=> b = 10  

So the form of the line is: s = r + 10

Only picture 3 can present this situation, so we choose it.

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