[tex]\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &500\\ t=\textit{elapsed time}\dotfill &20000\\ h=\textit{half-life}\dotfill &5730 \end{cases} \\\\\\ A=500\left( \frac{1}{2} \right)^{\frac{20000}{5730}}\implies A\approx 0.00000001555302367~Kgs[/tex]