Respuesta :

Answer:

C


Step-by-step explanation:

When we want probability of LESS THAN OR EQUAL TO 2, we need to take 0, 1, and 2.

We can add the number of editorials corresponding to p=0,1,2 and then divide that by total (200) to get our answer.

[tex]P(\leq2)=\frac{20+30+56}{200}\\P(\leq2)=\frac{106}{200}\\P(\leq2)=0.53[/tex]

Answer choice C is right.

Answer: c)  [tex]P(X\leq2)=0.53[/tex]

Step-by-step explanation:

By using the given frequency table in the picture, we need to find the value of

[tex]P(X\leq2)[/tex] i.i.e x is equal to at-most 2

For that we need to find the probability at x=0,1,2

Now,

 [tex]P(X=0)=\dfrac{20}{200}=0.1\\\\P(X=1)=\dfrac{30}{200}=0.15\\\\P(X=2)=\dfrac{56}{200}=0.28[/tex]

Now,

[tex]P(X\leq2)=P(X=0)+P(X=1)+P(X=2)\\\\\Rightarrow\ P(X\leq2)=0.1+0.15+0.28\\\\\Rightarrow\ P(X\leq2)=0.53[/tex]

Hence, the probability of 0-2 responses received to this week's newspaper editorials= [tex]P(X\leq2)=0.53[/tex]