1
thanks for your help!

Answer:
Solution is
[tex](\frac{1}{2},\frac{-3}{2})[/tex]
Which is Option C
Step-by-step explanation:
We are given the equations
4x - 6y = 11 ...............(i)
3x+y = 0 ..............(ii)
Now from equation (ii) we have
3x + y = 0
subtracting 3x from both sides we get
3x + y - 3x = 0 - 3x
y = -3x ....................(iii)
substituting this value in equation (i) which is
4x - 6y =11
Putting the value of y
4x - 6(-3x) = 11
4x + 18x = 11
22x = 11
Dividing both sides by 22
we get
[tex]\frac{22x}{22}=\frac{11}{22}[/tex]
or
x=[tex]\frac{1}{2}[/tex]
Now we have equation (iii) which tells us that
y= -3x
Putting value of x here
y = -3([tex]\frac{1}{2}[/tex])
It becomes
y = [tex]\frac{-3}{2}[/tex]
So
Solution set of the equation is
[tex](\frac{1}{2},\frac{-3}{2})[/tex]