The discriminant is 0. As the discriminant is 0 it will have equal roots.
And the real root is -2/3.
What is a Quadratic Equation?
In algebra, a quadratic equation is any equation that can be rearranged in a standard form where x represents an unknown, and a, b, and c represent known numbers, where a ≠ zero.
Conclusion: If a = zero, then the equation is linear, no longer quadratic, as there's no ax^2 term.
9[tex]x^{2}[/tex]+12x+4=0
a = 9 ; b = 12; c = 4;
discriminant = Δ = [tex]b^{2}[/tex] - 4ac
Δ = [tex]12^{2}[/tex] - (4*9*4) = 144 - 144 = 0
roots of quadratic equations are [ (-b ± √Δ)/ 2a)]
let roots of eqation are x1 & x2
As discriminant is zero so, x1=x2
x1 = x2 = -b/2a = - 12/(2*9) = -2/3
learn more about quadratic equations here https://brainly.com/question/1214333
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