The total pressure of a mixture of three gases in container is 3,345 mmHg. Gas #1 has a pressure of 988 mmHg and Gas #2 has a pressure of 1289 mmHg. What is the pressure of gas #3?

Respuesta :

According to Dalton's law of partial pressure: The pressure exerted by a mixture of gases is sum partial pressure of each gas exert on the container.

[tex]P_{total}=p_{1}+p_{2}+p_{3}.......[/tex]

Here we have mixture of three gases so the total pressure of three gases will be sum of their individual or partial pressures

[tex]P_{total}=p_{1}+p_{2}+p_{3}=3345=988+1289+p_{3}[/tex]

Therefore the partial pressure of third gas will be

[tex]p_{3}=3345-(988+1289)=1068mmHg[/tex]

The pressure of gas#3 is 1068mmHg