Find the expected value of a random variable x having the following probability distribution.
x (-5,-1,0,1,5,8)
Probability (.12, .16, .28, .22, .12, .1)

Respuesta :

Answer:

The expected value is 0.86.

Step-by-step explanation:

To find the expected value, multiply each x value by the corresponding probability, and then sum up these products:


(-5)(0.12) + (-1)(0.16) + (0)(0.28) + 1(0.22) + 5(0.12) + 8(0.10).

This comes out to

-0.60 - 0.16 + 0 + 0.22 + 0.60 + 0.8 = 0.86

The expected value is 0.86.

What is expected value?

The sum of the variables of a random variable with each variable multiplied by its probability of occurrence.

Given the following:

x:         -5        -1         0         1        5        8

P(x):   0.12    0.16    0.28    0.22   0.12    0.1

Expected value = sum of [x [tex]*[/tex] p(x)]

sum of [tex][x * p(x)][/tex]

[tex]= (-5*0.12) + (-1*0.16) + (0*0.28) + (1*0.22) + (5*0.12) + (8*0.1)[/tex]

= -0.60 - 0.16 + 0 + 0.22 + 0.60 + 0.8

= 0.86

Therefore, the expected value is 0.86.

To learn more about the expected value

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