If a 12 cm altitude to the hypotenuse of a right triangle divides the hypotenuse into segments with ratio 3:2, what is the length of the hypotenuse

Respuesta :

Answer:

The length of hypotenuse is [tex]10\sqrt{6}[/tex] cm

Step-by-step explanation:

Let's  length of hypotenuse is x

Since, a 12 cm altitude to the hypotenuse of a right triangle divides the hypotenuse into segments with ratio 3:2

so,

First part of hypotenuse length is

[tex]=\frac{3}{5}x[/tex]

Second part of hypotenuse length is

[tex]=\frac{2}{5}x[/tex]

now, we can draw triangle

We can see that

triangles ABD and ABC are similar

so, the ratio of their sides must be equal

[tex]\frac{\frac{3x}{5} }{12}=\frac{12}{\frac{2x}{5}}[/tex]

now, we can solve for x

[tex]\frac{3x}{5}\times\frac{2x}{5}=144[/tex]

[tex]6x^2=3600[/tex]

[tex]x=10\sqrt{6}[/tex]

So,  

The length of hypotenuse is [tex]10\sqrt{6}[/tex] cm

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