Answer:
(13)
[tex]f(3)=6[/tex]
(47)
[tex]x\leq -5[/tex]
Or
[tex]x\geq -2[/tex]
(48)
[tex]x<-7[/tex]
Or
[tex]x\geq 1[/tex]
Step-by-step explanation:
(13)
we are given graph of f(x)
we can locate x=3 on graph
so, we get
[tex]f(3)=6[/tex]
(47)
we are given
[tex]x+7\leq 2[/tex]
Subtract both sides by 7
[tex]x+7-7\leq 2-7[/tex]
[tex]x\leq -5[/tex]
Or
[tex]\frac{x+14}{4} \geq 3[/tex]
Firstly, we will multiply both sides by 4
[tex]4\times \frac{x+14}{4} \geq 4\times 3[/tex]
[tex]x+14 \geq 12[/tex]
Subtract both sides by 14
[tex]x+14-14 \geq 12-14[/tex]
[tex]x\geq -2[/tex]
now, we can locate it on number line
we get
(48)
we are given
[tex]3x+5<-16[/tex]
Subtract both sides by 5
[tex]3x+5-5<-16-5[/tex]
[tex]3x<-21[/tex]
Divide both sides by 3
[tex]x<-7[/tex]
Or
[tex]-5x-8\leq -13[/tex]
Add both sides by 8
[tex]-5x-8+8\leq -13+8[/tex]
[tex]-5x\leq -5[/tex]
Divide both sides by -5
we get
[tex]x\geq 1[/tex]
now, we can draw on number line
and we get
