The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y. y=3 x10^8/x what are the wavelengths for X-rays within frequency 3 x 10^18

The inverse variation equation shows the relationship between wavelength in meters x and frequency y y3 x108x what are the wavelengths for Xrays within frequenc class=

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Answer:

First option: 1*10^(-10) m

Step-by-step explanation:

y=3*10^8/x

Wavelength (in meters): x=?

Frequency: y=3*10^18

Replacing y by 3*10^18 in the equation:

3*10^18=3*10^8/x

Solving for x: Cross multiplication:

3*10^18*x=3*10^8

Dividing both sides of the equation by 3*10^18:

3*10^18*x/(3*10^18)=3*10^8/(3*10^18)

Simplifying:

x=10^8/10^18

x=10^(8-18)

x=10^(-10)

x=1*10^(-10) m

Answer:

[tex]1*10^{-10} m[/tex]

Step-by-step explanation:

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y.

[tex]y=\frac{3*10^8}{x}[/tex]

x is the wavelength and y is the frequency

we are given with frequency 3*10^18

we plug in 3*10^18 for y

[tex]3*10^{18}=\frac{3*10^8}{x}[/tex]

cross multiply it

[tex]3*10^{18}* x= 3*10^8[/tex]

divide by 3*x10^18 on both sides

[tex]x=\frac{3*10^8}{3*10^{18}}[/tex]

[tex]x=\frac{1}{10^{10}}[/tex]

or x= 1*10^-10 m