Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. The magnitude of q1 is 3 times the magnitude of q2 . At which point a on the axis is the electric field zero?

Respuesta :

d = distance between the two point charges = 60 cm = 0.60 m

r = distance of the location of point "a" where the electric field is zero from charge [tex]q_{1}[/tex] between the two charges.

[tex]q_{1}[/tex] = magnitude of charge on one charge

[tex]q_{2}[/tex] = magnitude of charge on other charge

[tex]q_{1}[/tex] = 3 [tex]q_{2}[/tex]

[tex]E_{1}[/tex] = Electric field by charge [tex]q_{1}[/tex] at point "a"

[tex]E_{2}[/tex] = Electric field by charge [tex]q_{2}[/tex] at point "a"


Electric field by charge [tex]q_{1}[/tex] at point "a" is given as

[tex]E_{1}[/tex] = k[tex]q_{1}[/tex] /r²

Electric field by charge [tex]q_{2}[/tex] at point "a" is given as

[tex]E_{2}[/tex] = k[tex]q_{2}[/tex] /(d-r)²

For the electric field to be zero at point "a"

[tex]E_{2}[/tex] = [tex]E_{1}[/tex]

k[tex]q_{2}[/tex] /(d-r)² = k[tex]q_{1}[/tex] /r²

[tex]q_{2}[/tex] /(d-r)² = 3[tex]q_{2}[/tex] /r²

1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm