Answer:
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Step-by-step explanation:
we are given height equation as
[tex]h=-16t^2+25t+5[/tex]
where
h is the height in feet of a Juggler's ball after t seconds
now, we can plug t=1.5
[tex]h=-16(1.5)^2+25(1.5)+5[/tex]
we can solve for h
[tex]h=42.5-16\cdot \:1.5^2[/tex]
[tex]h=42.5-36[/tex]
[tex]h=6.5[/tex]
So,
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
