Answer:
(i)
y-intercept is -2
(ii)
slope is [tex]\frac{2}{3}[/tex]
(iii)
slope is positive
(iv)
another point is (3,0)
Step-by-step explanation:
We are given equation as
[tex]y=\frac{2}{3} x-2[/tex]
now, we can compare it with slope intercept form of line
y=mx+b
where
m is slope
b is y-intercept
we get
[tex]m=\frac{2}{3}[/tex]
[tex]b=-2[/tex]
So,
(i)
y-intercept is -2
(ii)
slope is [tex]\frac{2}{3}[/tex]
(iii)
we can see that
[tex]m=\frac{2}{3}[/tex]
is a fraction and positive
so, slope is positive
(iv)
we can select any random value of x and find y
that will give us second point
Let's assume
x=3
[tex]y=\frac{2}{3}\times 3-2[/tex]
[tex]y=2-2[/tex]
[tex]y=0[/tex]
So, another point is (3,0)
(v)
Graph:
