Solve the system of equation please help , I would greatly appreciate it

Answer: Your answer is going to be D. (10, -1)
Step-by-step explanation:
Starting off the equation you want to get rid of either x or y ( I did x first)
Take x+3y=7 and multiply the entire equation by -2 -- -2(x+3y=7)
You get -2x-6y=-14 and then add the two equations together
-2x-6y=-14
2x-4y=24 -- You get -10y = 10
y = -1
You can take the -1 and plug it back into either equation.. ( I did x+3y=7)
x+3(-1)=7 -- x-3=7 -- Add the 3 to get the 10 ( x = 10 )
So you have x = 10 & y = -1
(10,-1)
Answer:
x = 10; y = -1
(10, -1)
D is your answer.
Step-by-step explanation:
To solve this system of equations, the first step is to to solve for a variable in each equation. I will solve for x in the first one and y in the second.
Part 1: Get x by itself in the first equation
x + 3y = 7
x + 3y - 3y = 7 - 3y
x = 7 - 3y
Part 2: Get y by itself in the second equation
2x - 4y = 24
-4y + 2x - 2x = 24 - 2x
-4y / -4 = (24 - 2x) / -4
y = -6 + 1/2x
New system of equations:
{x = 7 - 3y
{y = -6 + 1/2x
Part 3: Solve for x using substitution
x = 7 - 3(-6 + 1/2x)
x = 7 + 18 - 3/2x
x = 25 - 3/2x
x + 3/2x = 25 - 3/2x + 3/2x
5/2x = 25
(5/2x)(2/5) = 25(2/5)
x = 10
Part 4: Solve for y using substitution
y = -6 + 1/2(10)
y = -6 + 5
y = -1