Answer:
[tex]x=-\pi[/tex]
[tex]x=-2\pi[/tex]
Step-by-step explanation:
we are given
[tex]f(x)=sin(x)[/tex]
Any function crosses x-axis when it's y-value becomes 0
so, we can set
f(x)=0
and then we can solve for x
[tex]f(x)=sin(x)=0[/tex]
[tex]sin(x)=0[/tex]
we can use unit circle
and we get
[tex]x=\pi,2\pi[/tex]
but we need angle on [−2π,0)
so, we can put negative sign
and we get
[tex]x=-\pi[/tex]
[tex]x=-2\pi[/tex]
Answer:
Correct answer:
−2π
−π
Step-by-step explanation:
If we look at the graph of f(x)=sinx over [−2π,0), we see that the graph crosses the x- axis in two spots; x=−2π and x=−π. We do not include x=0 because we are looking at f(x)=sinx from −2π up to but not including 0..
