If f(x)=x over 2-3 and g(x)=3x^2+x-6 find (f+g)(x)

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carlosego carlosego · Answer 1 · 2019-01-17T15:58:45+01:00

Answer:

[tex](f + g)(x) = 3x ^ 2 + \frac{3}{2}x - 9[/tex]

Step-by-step explanation:

We are asked to find (f + g) (x)

In this case what we must do is add the function f (x) with the function g (x). So, we have:

[tex]f(x) = \frac{1}{2}x - 3\\g (x) = 3x ^ 2 + x - 6\\(f + g) (x) = f(x) + g (x)\\(f + g) (x) = \frac{1}{2}x - 3 + 3x ^ 2 + x - 6[/tex]

Finally we simplify, and we have left:

[tex](f + g)(x) = 3x ^ 2 + \frac{3}{2}x - 9[/tex]

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alinakincsem alinakincsem · Answer 2 · 2019-01-17T19:03:23+01:00

Answer:

[tex](f + g) (x) =3x^{2} +\frac{3}{2}x-9[/tex]

Step-by-step explanation:

We are given the following two functions and we are to add them:

[tex] f (x) = \frac {x} {2} -3 [/tex]

[tex] g (x) = 3x^{2} + x - 6 [/tex]

Adding these two functions, we get:

[tex] (f + g) (x) = f (x) + g (x) [/tex]

[tex] (f + g) (x) = \frac {1} {2} x - 3 + 3x^{2} + x - 6 [/tex]

Adding the like terms together and simplifying them to get:

[tex] (f + g) (x) = 3x^{2} + \frac {3}{2} x - 9 [/tex]