Respuesta :
Answer: The mass of methanol produced is 12 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For carbon monoxide :
Given mass of carbon monoxide = 14 g
Molar mass of carbon monoxide= 28 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of carbon monoxide}=\frac{14g}{28g/mol}=0.5mol[/tex]
- For hydrogen gas:
Given mass of hydrogen gas = 1.5 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of hydrogen gas}=\frac{1.5g}{2g/mol}=0.75mol[/tex]
The chemical equation for the reaction of carbon monoxide and hydrogen gas follows:
[tex]CO+2H_2\rightarrow CH_3OH[/tex]
By Stoichiometry of the reaction:
2 moles of hydrogen gas reacts with 1 mole of carbon monoxide
So, 0.75 moles of hydrogen gas will react with = [tex]\frac{1}{2}\times 0.75=0.375mol[/tex] of carbon monoxide
As, given amount of carbon monoxide is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of hydrogen gas produces 1 mole of methanol
So, 0.75 moles of hydrogen gas will produce = [tex]\frac{1}{2}\times 0.75=0.375moles[/tex] of methanol
Now, calculating the mass of methanol from equation 1, we get:
Molar mass of methanol = 32 g/mol
Moles of methanol = 0.375 moles
Putting values in equation 1, we get:
[tex]0.375mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.375mol\times 32g/mol)=12g[/tex]
Hence, the mass of methanol produced is 12 grams
