Answer:
Step-by-step explanation:
Given that Elijah threw a ball from a height of 4 feet. The ball reached maximum height of 16 feet after 2seconds
Let vertical component of his speed be v
When it reaches maximum height its velocity becomes 0
Hence
height reached by the ball =[tex]h=vt-\frac{gt^2}{2}[/tex]
When h=12(16-4) we get g=gravity =32
Hence 12 =2v-16(4)
v=38
Hence [tex]h=38t-\frac{32t^2}{2}[/tex]
where h is calculated from the height of hand i.e. 4 feet
When it touches the ground h =-4
When it starts falling then distance travelled = 16 feet
Initial velocity =0 Accn due to gracity =32 feet
Using these we can write
[tex]16=0+\frac{32t^2}{2}\\ t=1[/tex]
So after 3 minutes from start the ball would reach the ground
