Answer:
C₆H₁₀Cl₂
Step-by-step explanation:
Step 1. Calculate the empirical formula
a. Calculate the moles of each element
Moles of C = 72.62 g C × (1 mol C/12.01 g C) = 6.0466 mol C
Moles of H = 9.885 g H × (1 mol H/1.008 g H) = 9.8065 mol H
Moles of Cl = 69.50 g Cl × (1 mol Cl/35.45 g Cl) = 1.9605 mol O
b. Calculate the molar ratio of each element
Divide each number by the smallest number of moles and round off to an integer
C:H:Cl = 6.0466:9.8065:1.9605
C:H:Cl = 3.084:5.002:1
C:H:Cl ≈ 3:5:1
c. Write the empirical formula
EF = C₃H₅Cl
Step 2. Calculate the molecular formula
EF Mass = 76.52 u
MF mass = 153 u
MF = (EF)_n
n = MF Mass/EF Mass
n = 153 u/76.52 u
n = 1.999 ≈ 2
MF = (C₃H₅Cl)₂
MF = C₆H₁₀Cl₂
