Answer: [tex]f(x)=\dfrac{2000x-x^2}{2}[/tex]
Step-by-step explanation:
Perimeter (P) is the total length of the fencing which covers 2 sides of one length and 1 side of another length (because the side along the river does not need fencing). So, P = 2L+ x where L is the length and x is the width.
P = 2000 and P = 2L + x → 2000 = 2L + x
[tex]\text{Solve for L:}\\\\2000 = 2L + x\\\\2000-x=2L\\\\\dfrac{2000-x}{2}=L[/tex]
Area (A) is length x width → A = L × x
[tex]\text{Use substitution to replace L with}\ \dfrac{2000-x}{2}\\\\A = f(x)=\bigg(\dfrac{2000-x}{2}\bigg)x\\\\\\.\qquad \qquad =\dfrac{2000x-x^2}{2}[/tex]