Answer:
Step-by-step explanation:
Don't be fooled by this. We can make this look like the equations you have been factoring up to now. Let
x^3 = y Square both sides of the equation
(x^3)^2 = y^2
x^6 = y^2
Now substitute these results into the given equation.
y^2 + 6y + 5 = 0
This factors
(y + 5)(y + 1) = 0
So either y + 5 = 0
or y + 1 = 0
y+5 = 0
x^3 + 5 =0
x = cuberoot(-5)
x^3 + 1 = 0
x^3 = - 1
cube root (x^3) = cube root (-1)
x = - 1
Essentially the graph shows that there are only 2 roots (-1,0) (-1.71,0) just as our solution suggests.
