lulu5537
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What is the factorization of the trinomial below 3x^3+6x^2-24x
A) 3(x-2)(x+4)
B) 3(x^2-2)(x+4)
C) 3x(x-2)(x-4)
D) 3x(x-2)(x+4)

Respuesta :

D  3x(x-2)(x+4) because you have to take out 3x (x^2+2x-8) and then appling delta/4 to x^2+2x-8 you have x1,2 = -1+-3= -4 and +2

D

take out a common factor of 3x from each term

= 3x(x² + 2x - 8 )

= 3x(x + 4)(x - 2)


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