The solution set of the inequality is [tex]\boxed{x < \frac{{23}}{7}}{\text{ or }}\boxed{x = 3\frac{2}{7}}.[/tex]
Further explanation:
Explanation:
If the linear equality is [tex]x < b[/tex], than the solutions of the inequality lies with in [tex]\boxed{\left( { - \infty ,b} \right)}.[/tex]
If the linear equality is [tex]x > b[/tex], than the solutions of the inequality lies with in [tex]\boxed{\left( {b,\infty } \right)}.[/tex]
The given statement is 3 more than the product of 7 and a number x is less than 26.
The inequality from the statement can be obtained as follows,
[tex]3 + 7x < 26[/tex]
Solve the above inequality to obtained solution.
[tex]\begin{aligned}3 + 7x &< 26\\ 3 + 7x - 3 &< 26 - 3 \\ 7x &< 23\\\frac{{7x}}{7} &< \frac{{23}}{7}\\ x &< \frac{{23}}{7}\\x &< 3\frac{2}{7}\\\end{aligned}[/tex]
The solution set of the inequality is [tex]\boxed{x < \frac{{23}}{7}}{\text{ or }}\boxed{x = 3\frac{2}{7}}.[/tex]
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Linear inequality
Keywords: inequality, statement, product, 3, more, number, less than, solution, solution set, fraction, integer, x.
