Question says to find the diagonal of the rectangular solid given in the picture.
So we can use formula of the diagonal of the rectangular solid .
Which is given by :
[tex]d= \sqrt{l^2+w^2+h^2}[/tex]
there d is the diagonal which we need to find
l = length = 5 ft
w = width = 4 ft
h = height = 3 ft
Now plug these values into above formula:
[tex]d= \sqrt{5^2+4^2+3^2}[/tex]
[tex]d= \sqrt{25+16+9}[/tex]
[tex]d= \sqrt{50}[/tex]
[tex]d= 5\sqrt{2}[/tex]
Hence final answer is [tex]diagonal= 5\sqrt{2}[/tex] ft.
