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In a particular reaction between copper metal and silver nitrate, 12.7 g Cu produced 38.1 g Ag. What is the percent yield of silver in this reaction?

Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

A) 88.4%
B) 176%
C) 56.7%
D) 77.3%

Respuesta :

malika8888
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
63.5 g. ----------------> 216 g
12.7 g ----------------> x
[tex]x = \frac{12.7 \times 216}{63.5} \\ x = 43.2\: g[/tex]

[tex]43.2 \: g = 100\% \\ 38.1 \: g = y \\ y = \frac{38.1 \times 100}{43.2} \\ y = 88.19\%[/tex]
Answer: A) 88.2 %