Answer : The potassium ion concentration in units of mol/L is, [tex]3.5\times 10^{-2}mol/L[/tex]
Explanation :
As we are given that the concentration of potassium ion in the solution is 35 meq/L. Now we have to determine the potassium ion concentration in units of mol/L.
First we have to convert meq/L to eq/L.
Conversion used :
1 meq/L = 10⁻³ eq/L
As, 1 meq/L concentration of potassium ion = 10⁻³ eq/L
So, 35 meq/L concentration of potassium ion = 35 × 10⁻³ eq/L
As we know that:
[tex]\text{Moles}=\frac{\text{Gram equivalent}}{n_f}[/tex]
where,
[tex]n_f[/tex] = n- factor or valency of ion
[tex]n_f[/tex] for potassium ion = 1
So, the concentration of potassium ion = [tex]\frac{35\times 10^{-3}mol/L}{1}=3.5\times 10^{-2}mol/L[/tex]
Therefore, the potassium ion concentration in units of mol/L is, [tex]3.5\times 10^{-2}mol/L[/tex]
