Let x be the bigger number and y be the smaller number.
One number is 11 more than twice another number. Thus,
x = 2y + 11
The sum of the numbers is twice their difference, thus,
x + y = 2(x-y), which simplifies to:
x + y = 2x - 2y
3y = x (Now plug this back to the first equation:
3y = 2y + 11, and solve:
y = 11
Plug in y = 11 to the first equation:
x = 2(11) + 11 = 22 + 11 = 33
Thus the numbers are: x = 33, y = 11.
