[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\J(\stackrel{x_1}{2}~,~\stackrel{y_1}{-1})\qquadK(\stackrel{x_2}{2}~,~\stackrel{y_2}{5})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\JK=\sqrt{[2-2]^2+[5-(-1)]^2}\implies JK=\sqrt{(2-2)^2+(5+1)^2}\\\\\\JK=\sqrt{0+6^2}\implies JK=6[/tex]
Answer:
Distance between j and k = 6 units
Step-by-step explanation:
Following formula is used to find the distance between two points:
Distance = [tex]\sqrt{(x_{1} - x_{2} )^{2} + (y_{1} - y_{2} )^{2}[/tex]
We are given two points j (2,-1) and k (2,5)
so putting in the values for [tex]x_{1} , x_{2} , y_{1} and y_{2}[/tex], we get:
[tex]\sqrt{(2 - 2)^{2} + (- 1 - 5)^{2} }[/tex]
= [tex](\sqrt{( 0 )^{2} + (-6)^2}[/tex]
= [tex]\sqrt{36}[/tex]
= 6
Therefore, the distance between the two points j and k is 6 units.
