What is the remainder when the function f(x)=x^4 - 3x^3 +7x - 1 is divided by (x-2)

Answer: Second option. 5}
Solution
To find the remainder of a function when is divided by x-a, you only have to find f(a). In this case we must divide by x-2, then a=2 and we must determine f(2):
x=a=2→f(x)=f(a)=f(2)=(2)^4-3(2)^3+7(2)-1
f(2)=16-3(8)+14-1
f(2)=16-24+14-1
f(2)=5
Answer: the remainder is 5
Answer: 5 (The second option).
Step-by-step explanation:
1. To divide [tex]f(x)=x^4-3x^3+7x-1[/tex] by [tex](x-2)[/tex] you must complete the polynomial with the missing term [tex]0x^{2}[/tex]:
[tex]f(x)=x^4-3x^3+0x^{2}+7x-1[/tex]
2. Write the coefficients of the polynomial and solve for [tex]x[/tex] in the deminator to find the number to write in the division:
[tex]x-2=0\\x=2[/tex]
3. Write the first coefficient under the line, multiply 2 by this coefficient and substract the result with the next coefficient. Multiply the result of the substraction by 2 and repeat the proccedure this with each coefficient:
2 | 1 -3 0 7 -1
1 2 -2 -4 6
___________
-1 -2 3 5
4. The remainder is 5.