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three players scored a total of 70 points during a basketball game one player scored twice as many as one mate and 10 points fewer than the other teammate. how many points did each player score

Respuesta :

40+20+10=70
40 is twice 20
10 is 10 fewer than 20.
aachen

Answer:

24, 12 and 34.

Step-by-step explanation:

Let points of all three players are [tex]x_1,\ x_2,\ x_3[/tex] respectively.

It is given that sum of their score is 70.

Therefore, [tex]x_1+x_2+x_3=70[/tex]. ...1

Also, score of one is twice the other.

So, [tex]x_1=2x_2[/tex].   ...2

It is also given that its score is 10 points less than the other one.

Therefore, [tex]x_1=x_3-10[/tex]  ...3

Solving all three equations we get,

[tex]x_1=24, \ x_2=12,\ x_3=34[/tex].

Hence,it is the required solution.

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