angiebelle18
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The gravity of mars is 3.69 meters/second^2. if you had a pendulum on mars that was 1.8 meters long, what would the period be?

A.) 3.9 seconds
B.) 3.2 seconds
C.) 0.87 seconds
D.) 5.2 seconds
E.) 4.4 seconds

Respuesta :

zainabekram2

Given that,

g= 3.69 m/s2

L= 1.8 m

T=?

Since, for pendulum: T= 2π√(L/g)

T= 2*3.14*√(1.8/3.69)

T= 4.388 s

or

Time period = 4.4 seconds



alinakincsem

Answer:

E.) 4.4 seconds

Explanation:

We know that,

T = [tex]2\pi \sqrt{l/g}[/tex]

and we are given the following:

gravity of mars (g) = 3.69 meters/[tex]second^{2}[/tex]

length of pendulum (l) = 1.8 meters

To find the period of the pendulum, put the given values in the formula above:

T = [tex]2\pi \sqrt{l/g}[/tex]

T = 2 x 3.14 x [tex]\sqrt{1.8/3.69}[/tex]

T = 4.388 which can be rounded off to get 4.4 seconds.

Therefore, the correct answer option is E.) 4.4 seconds.

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