Find the coordinates of point, P, which divides the line segment from A = (4, 0) to B = (6, 8) in a ratio of 1:2.

Given the points
A(x₁,y₁) = (4,0)
B(x₂,y₂) = (6,8)
ratio l:m = 1:2
The formula that we use to find the point P that divides the given line segment in the ratio l:m is
P(x,y) = [tex](\frac{lx2+mx1}{l+m} ,\frac{ly2+my1}{l+m} )[/tex]
=[tex](\frac{1.6+2.4}{1+2} , \frac{1.8+2.0}{1+2} )[/tex]
=[tex](\frac{6+8}{3} ,\frac{8+0}{3} )[/tex]
=[tex](\frac{14}{3}, \frac{8}{3} )[/tex]
Hence the right option is B)
Answer:
Then point P is ([tex]\frac{14}{3}, \frac{8}{3}[/tex])
The correct answer is option 2.
Step-by-step explanation:
First let's calculate the distance between points A and B
A: (4.0)
B: (6.8)
The distance in x between both is:
[tex]X_2-X_1 = 6-8 = 2[/tex]
The distance in the y axis between both is:
[tex]y_2-y_1 = 8-0 = 8[/tex].
We know that the point divides the line segment in a 1: 2 ratio as shown in the following diagram
A --------- P ------------------- B
Where the distance PB is twice as large as the AP distance.
Then [tex]AP = \frac{1}{3}AB\\\\PB = \frac{2}{3}AB.[/tex]
Therefore Point P is at a distance d = 1/3 * ([tex]X_{2}-X_{1}[/tex]) from point A.
So:
[tex]P_{x} = 4 + \frac{1}{3}2 = \frac{14}{3}\\\\P_{y} = 0 + \frac{1}{3}8 = \frac{8}{3}[/tex]
Then point P is ([tex]\frac{14}{3}, \frac{8}{3}[/tex])
The correct answer is option 2.