contestada

What is the justification for each step in solving the inequality?
−2(x+1)≥3x+8
Select from the drop-down menus to correctly justify each step.

−2(x+1)≥3x+8 Given
−2x−2≥3x+8
−2x≥3x+10
−5x≥10
x≤−2

Respuesta :

prayag11
[tex]<b>HELLO ANNA!![/tex]

Given inequality
=> −2(x+1)≥3x+8
=>
[tex] - 2x - 2 \geqslant 3x + 8 \\ \\ add \: 2 \: in \: both \: sides \\ \\ - 2x \geqslant 3x + 10 \\ \\ subtract \: with \: - 3x \: in \: both \: sides \: \\ \\ - 5x \geqslant 10 \\ [/tex]

now multiply with - on both sides.

As we know now sign will change
=> 5x >_ -10

Now divide by 5 on both sides
=> x >_ -2
HOPE IT HELPED YOU.

Hi Anna,

Question:

What is the justification for each step in solving the inequality?

−2(x+1)≥3x+8

Select from the drop-down menus to correctly justify each step.

Solution:

−2x − 2 ≥ 3x + 8

Subtract 3x from both sides.

−2x − 2 − 3x ≥ 3x + 8 − 3x

−5x − 2 ≥ 8

Add 2 to both sides.

−5x − 2 + 2 ≥ 8 + 2

−5x ≥ 10

Divide both sides by -5

x = -2

Answer:

The only step she needs to fix is option C instead of being −2x ≥ 3x + 10 it should be  −2x − 2 − 3x ≥ 3x + 8 − 3x  then −5x − 2 + 2 ≥ 8 + 2 then divide both sides by 5. She needs to add those three steps.

Otras preguntas