Work done on the crate is given by
[tex]W = Fd cos\theta[/tex]
here we have
[tex]F = 142 N[/tex]
[tex]d = 6.1 m[/tex]
[tex]\theta = 37 degree[/tex]
now we have
[tex]W = Fdcos37[/tex]
[tex]W = 142 * 6.1 * cos37[/tex]
[tex]W = 691.8 J[/tex]
So it require 691.8 J work to slide the block across horizontal floor