We are given that
Shopkeeper has six coins
total number of coins =6
we know that
there are four types of coins
(1) cents
1 cent =1 cent
(2) nickels
1 nickel =5 cents
(3) dimes
1 dimes =10 cents
(4) quarters
1 quarter = 25 cents
so, we can use trial and error method
Since, nickels , dimes and quarter are multiple of 5
and there 38 cents
so, three coins must be cent
number of cent coins =3
so, the remaining cent = 38-3=35
so, possible coins can be 1 quarter and 2 nickels
1 quarter + 2 nickels =25+2(5)=35
so, coins were
Number of cents =3
Number of nickels =2
Number of dimes =0
Number of quarter =1..................Answer
