Twelve
A. All nitrates are soluble. Calcium Nitrate is a nitrate. It is soluble. Reason:2
B. All nitrates are soluble. Copper(1)Nitrate is a nitrate. It is soluble. Reason 2
I've never heard of Iron(1). You should check this out on one of your tables.
C. Iron(1)Chloride is soluble. All Chlorides (except those mentioned) are soluble. Iron (1) if it exists, is soluble. Reason: 3
D. Iron (II) Sulfate is not soluble. Reason: 6
E. Potassium Sulfate. All chemicals made from column 1 chemicals are soluble. This type of sulfate is soluble. Reason: 1 and 6.
Eighteen
Reaction Rate. In general, if you remove a product, the rate of reaction will increase.
If you add more of a product, the reaction rate will decrease. That's why as the reaction proceeds it slows down.
Based on these two statements. A is wrong. As more S2 is produced, the rate ought to decrease.
B is wrong as well. If you remove H2 the reaction rate should increase.
C is Correct. If B is wrong, C has to be correct. They are opposites.
D is Correct. If A is wrong, D has to be correct. They are opposites. One of them is correct.
E is correct. See if you can tell why.
Twenty One
Start with what you know for certain. E cannot be true. Activation Energy is usually decreased by the use of a Catalyst. It has the effect of making the reaction take place quicker and for the most part, the products are more favored than they were without the Catalyst.
B is the opposite of what would happen. The NO would help produce more SO3 not less.
C is wrong. NO would encourage the reaction between SO2 and O2 by lowering the activation energy.
D again, D is incorrect. The number of molecules of SO2 and O2 because the activation energy has been lowered.
E is false. The NO does exactly the opposite to E.
Note: You probably got notes with this question. You have to read them carefully to understand what is actually going on.
Activation energy looks like a camel's hump. A catalyst will lower the hump making products more easily formed.
Answer: There is only one thing that you can choose and that is A.
