solve for x can't remember how to do this for a circle and triangle through it.

Answer:
x = 2
Step-by-step explanation:
For secants that intersect at an external point, the product of the external length and total length is a constant.
... 3·(3 +5) = 4·(4 +x) . . . . . write the two products, and set them equal
... 24 = 16 +4x . . . . . . . . . . eliminate parentheses
... 8 = 4x . . . . . . . . . . . . . . .subtract 16
... 2 = x . . . . . . . . . . . . . . . . divide by 4
Answer:
[tex]x=2[/tex]
Step-by-step explanation:
(Refer the attachment to find ABCD and O points)
When two secant lines AD and CB intersects at a point outside the circle "O"
then,
OA*OD=OB*OC
Now we can substitute the values and find x.
[tex]3*8=4*(4+x)[/tex]
[tex]24=16+4x[/tex]
[tex]8=4x[/tex]
[tex]x=2[/tex]